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the first odd integer is 1 3 and the last odd integer is 7 8 1
The series of numbers form an arithmetic progression with a common difference of 2 . Let a 1 = 1 3 and a n = 7 8 1 .
a n = a 1 + ( n − 1 ) d ⟹ 7 8 1 = 1 3 + ( n − 1 ) 2 ⟹ 3 8 4 = n − 1 i m p l i e s n = 3 8 5
s = 2 n ( a 1 + a n ) ⟹ s = 2 3 8 5 ( 1 3 + 7 8 1 ) = 1 5 2 8 4 5