Find the sum of all solutions.

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Let 5 5 -tuples of positive integers ( x 1 ( 1 ) , . . . , x 5 ( 1 ) ) (x^{(1)}_{1},...,x^{(1)}_{5}) , ( x 1 ( 2 ) , . . . , x 5 ( 2 ) ) (x^{(2)}_{1},...,x^{(2)}_{5}) ,...., ( x 1 ( n ) , . . , x 5 ( n ) ) (x^{(n)}_{1},..,x^{(n)}_{5}) satisfy the following system of equations:

x i + x i + 1 = x i + 2 3 x_{i}+x_{i+1}=x_{i+2}^{3} , 1 i 5 1≤i≤5 x 6 = x 1 , x 7 = x 2 x_{6}=x_{1},x_{7}=x_{2} .

Find i = 1 n ( x 1 ( i ) + . . . + x 5 ( i ) ) \sum_{i=1}^{n}(x^{(i)}_{1}+...+x^{(i)}_{5})


The answer is 10.

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1 solution

Souryajit Roy
May 17, 2014

Let x x and y y be the largest and smallest of the numbers x 1 , . . . , x 5 x_{1},...,x_{5} .

Then, we get x 2 2 x x^{2}≤2x and y 2 2 y y^{2}≥2y .

Since x x and y y are both greater than o,we have 2 y x 2 2≤y≤x≤2 .Hence the equation has the unique solution x 1 = x 2 = x 3 = x 4 = x 5 = 2 x_{1}=x_{2}=x_{3}=x_{4}=x_{5}=2 .

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