The and terms of an arithmetic progression are and , respectively. Find the sum of the first terms of this progression.
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The n t h term of an arithmetic progression is given by a n = a m + ( n − m ) ( d ) where a m is the m t h term and d is the common difference.
Computing for d , we have
2 5 = − 2 + ( 2 0 − 2 ) ( d ) ⟹ d = 1 . 5
Computing for a 1 , we have
a 1 = − 2 + ( 1 − 2 ) ( 1 . 5 ) = − 3 . 5
The sum of the terms of an arithmetic progression is given by s = 2 n ( a 1 + a n ) where n is the number of terms, a n is the n t h term and a 1 is the first term. So we have
s = 2 2 0 ( − 3 . 5 + 2 5 ) = 2 1 5