find the sum of the first 20 terms of an A.P.

Algebra Level 1

The 2 n d 2^{nd} and 2 0 t h 20^{th} terms of an arithmetic progression are 2 -2 and 25 25 , respectively. Find the sum of the first 20 20 terms of this progression.


The answer is 215.

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1 solution

The n t h n^{th} term of an arithmetic progression is given by a n = a m + ( n m ) ( d ) a_n=a_m+(n-m)(d) where a m a_m is the m t h m^{th} term and d d is the common difference.

Computing for d d , we have

25 = 2 + ( 20 2 ) ( d ) 25=-2+(20-2)(d) \implies d = 1.5 d=1.5

Computing for a 1 a_1 , we have

a 1 = 2 + ( 1 2 ) ( 1.5 ) = 3.5 a_1=-2+(1-2)(1.5)=-3.5

The sum of the terms of an arithmetic progression is given by s = n 2 ( a 1 + a n ) s=\dfrac{n}{2}(a_1+a_n) where n n is the number of terms, a n a_n is the n t h n^{th} term and a 1 a_1 is the first term. So we have

s = 20 2 ( 3.5 + 25 ) = 215 s=\dfrac{20}{2}(-3.5+25) = 215

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