1+3+5+7+. . . . . . .+19 = ? ? ?
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This is an arithmetic sequence with first term a 1 = 1 and common difference d = 2 . Thus, the general term is given by a n = a 1 + ( n − 1 ) d = 2 n − 1 . We can figure out how many terms are in the sequence by solving for n for the last given term:
a n = 2 n − 1 = 1 9 ⇒ n = 1 0
And the sum of the first n terms of an arithmetic sequence is given by:
S n = 2 n ( a 1 + a n ) ⇒ S 1 0 = 2 1 0 ( 1 + 1 9 ) = 1 0 0
Ever Shorter; sum of first n odd numbers is n 2 .
219#7 ( right )
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sum of the n odd numbres_
1 + 3 + 5 + 7 + . . . . . . .+ n
= n^2 ( n term )