3 liquids which can't react with each other chemically are mixed together in a calorimeter.
What is the temperature of all 3 liquids when they are in heat equilibrium? Type your answer in Celcius degree .
Note: Assume that there is no heat escaping from the calorimeter and no heat flow between the calorimeter and the liquids. Moreover, no liquids turn solid or into gases.
The mass, specific heat capacity and temperature of each liquid is given in the table below:
Liquids | # | # | # |
Mass ( ) | |||
Specific heat capacity ( ) | |||
Temperature ( ) |
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Let the masses be m 1 , m 2 , m 3 . Let the specific heats be C 1 , C 2 , C 3 . Let the initial temperatures be T 1 , T 2 , T 3 , and the final temperature be T . Determine a value of T such that the net gain/loss of energy is zero.
m 1 C 1 ( T − T 1 ) + m 2 C 2 ( T − T 2 ) + m 3 C 3 ( T − T 3 ) = 0
Solving for T yields T = − 1 9