Let be a linear transformation such that and . If a matrix is the standard matrix of , find .
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We have A ( 3 0 2 1 ) = ( 1 2 5 4 ) and hence A = ( 1 2 5 4 ) ( 3 0 2 1 ) − 1 = 3 1 ( 1 2 1 3 8 ) Thus d e t ( 3 A ) = ∣ ∣ ∣ ∣ 1 2 1 3 8 ∣ ∣ ∣ ∣ = − 1 8