Find the unit digit

Find the units digit of

123456789101 1 96 + 1920382719391816 1 99 . 1234567891011^{96}+19203827193918161^{99}.


The answer is 2.

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5 solutions

Harish Chauhan
Jul 24, 2014

(123...1011)^96+(192....161)^99

In this expression last digit of both will be 1

so sum is =1+1=2

Unit place of power of number having unit place 1 is 1 .So,(1234..... )^96+ (190......)^99=1+1=2

Zarif Hosain
Jul 14, 2014

1 raised to the power of any number is one therefore 1^x + 1^y =1+1 = 2 ie the answer

Sunil Pradhan
Jul 6, 2014

1^ any power having unit digit 1

1 + 1 = 2

The unit digit of both number is 1. So, the unit digit both of the result is also 1. Then, the unit digit of the sum is 2

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