Find the Unit Digits!

We consider $\pmod{10}$ . Since $1234567891011\equiv 1\pmod{10},$ we have

$1234567891011^{2002}\equiv 1^{2002} \pmod{10}\equiv \boxed{1}\pmod{10},$

and we are done.

Note that to figure this out, we only have to consider the last digit of the number, which is 1. 1 to the power of anything is still one, thus the answer is of course $\boxed{1}$ .

The units digit of the original number is 1.

This 1 ^ 2002 is 1.

So the answer is 1.

Just take mod 10. Usually for more complex problems of these types it is useful to use Fermat's little theorem.

1 1 1 1 1 .... 1=1

2002=_2(mod4) as 1^2=1 hence we get 1234567891011^2002 's units place=1

If the number having 1 at unit place . Then any power of that number having unit place 1.

this is a easy one all you need to know is that 1x1 = 1 no matter how many time u do it. In this case it has been raised to the power of 2002. So if u multiply 1 with 1 2002 times it will still remain 1

Any Number Of The Type (abcedfg...1)^É where "a,b,c,d,e,f,g,....." are integers from 0 to 9 and É belongs to integers gives the units digit to be \boxed{1}

1^ any number is having 1 in the unit place.