Find the value of expression!

Algebra Level 3

Find the value of the sum below.

18 35 + 18 × 2 35 + 18 × 3 35 + + 18 × 33 35 + 18 × 34 35 \left \lfloor \frac {18}{35} \right \rfloor + \left \lfloor \frac {18\times 2}{35} \right \rfloor + \left \lfloor \frac {18 \times 3}{35} \right \rfloor + \cdots + \left \lfloor \frac {18 \times 33}{35} \right \rfloor + \left \lfloor \frac {18 \times 34}{35} \right \rfloor

Notation: \lfloor \cdot \rfloor denotes the floor function .


The answer is 289.

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1 solution

Let the sum be S S . Then we have:

S = n = 1 34 18 n 35 = n = 1 34 ( 17.5 + 0.5 ) n 35 = n = 1 34 n 2 + n 70 for n < 70 n 70 = 0 = n = 1 34 n 2 = 0 + 1 + 1 + 2 + 2 + + 16 + 16 + 17 = 2 n = 1 16 n + 17 = 2 × 16 × 17 2 + 17 = 289 \begin{aligned} S & = \sum_{n=1}^{34} \left \lfloor \frac {18n}{35} \right \rfloor \\ & = \sum_{n=1}^{34} \left \lfloor \frac {(17.5+0.5)n}{35} \right \rfloor \\ & = \sum_{n=1}^{34} \left \lfloor \frac n2 + \blue{\frac n{70}} \right \rfloor & \small \blue{\text{for }n < 70 \left \lfloor \frac n{70} \right \rfloor = 0} \\ & = \sum_{n=1}^{34} \left \lfloor \frac n2 \right \rfloor \\ & = 0 + 1 + 1 + 2 + 2 + \cdots + 16 + 16 + 17 \\ & = 2 \sum_{n=1}^{16} n + 17 \\ & = 2 \times \frac {16\times 17}2 + 17 \\ & = \boxed{289} \end{aligned}

@Neeraj Anand Badgujar , there was nothing wrong with the previous version of your problem question. I am a moderator and I amended it. There were errors in your problem question. Generally, formally it is know as floor function and more longer greatest integer function. Brackets are not a proper symbol for floor function. It is used because people are not able to key the proper symbol through the keyboard. No need to mention how floor function works, Members are encouraged to use Brilliant.org's wiki through the link we provide as I have done in this problem. I am using a standard format of problem description in Brillaint.org. Please refer to other problems in Brilliant.org. Please don't change this problem again.

Chew-Seong Cheong - 11 months, 1 week ago

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@Chew-Seong Cheong ok sir
So you have the power to change anyone's problem?? , just asking.

A Former Brilliant Member - 11 months, 1 week ago

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Yes, a moderator can. I have editing problems to improve them,

Chew-Seong Cheong - 11 months, 1 week ago

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