Find the value of given question

Algebra Level 3

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28×sqrt{2} sqrt{2} 98 1

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1 solution

6^2=3^2x2^2 ; sqrt{98}=7xsqrt{2} ; sqtr[3]{1/25}= 5^(-2/3) ; 15^(-4/3)=3^(-3/4)x5^(-3/4) -> 3^-3x3^2x2^2x7xsqrt{2}/5^2x5^(-2/3)x5^(-4/3)x3^(-4/3)x3^-3 -> som the expoents -> Expoents of 3: -3+2-(-4/3)-1/3= 0 ; Expoets of 5: -2-(-2/3)-(-4/3)= 0 -> 2^2x7xsqrt{2} -> 28xsqrt{2}

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Marta Reece - 2 years, 12 months ago

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