A particle of mass m is moving in a circle of radius R such that its centripetal acceleration 'a' varies with time 't' as a = K , where K is a constant . Find the work done on the particle in first 't' seconds .
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Work-Energy theorem gives work done =change in kinetic energy in the first t seconds =(1/2)m(v^2)=(1/2)mkR(t^2)