find the ?

$\dfrac{18 × 4}{2} = 36\\ \dfrac{6 × 15}{2} = 45\\ \dfrac{x × 8}{2} = 44\\ x = \color{#69047E}{\boxed{11}}$

If you notice the in the first 3 numbers 4,36 and 18 if you divide 4/2=2 in which 2x9=18 which leads us to the conclusion that the number on the second box is always the result of the first number divided by 2 and the remains multiplied by the number on the third box.Notice that if we follow the same reasoning for the next 3 numbers we again discover the number on the second box: 6/2=3 3x15=44. So how do we discover what is the (?)?Simple we do the same that we did in the last ones! 8/2=4 4x(?)=44 so what number could be multiplied by 4 that give us 44?The number 11. So the answer is 11!!!

Let the desired number be denoted as $x$ .

Note that

$4\times 18 = 2\times 36$

$6\times 15=2 \times 45$

Hence, we have

$8x=2\times 44=88 \implies x=\boxed{11}.$

the sequence is like this: 36 ÷ 4 = 9, and 9 x 2 = 18 so we'll do that in the required figure: 44 ÷ 8 = 5.5, and 5.5 x 2 = 11

the answer is 11

Half of top no is multiplication of side number ,so 11X4 ==44 is result, Hence bottom number is 11 in this xcase Ans

K.K.GARG,India

36 = (18)(2), 45 = (15)(3), 44 = (n)(4) the multipliers are consecutive. solving for n. n= 11