Find this digit

Let y y denote a single-digit integer. The tens digit in the product of 2 y 7 \overline{2y7} and 39 39 is 9 9 . Find y y .


The answer is 8.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

Chew-Seong Cheong
Mar 22, 2020

2 y 7 × 39 = 39 ( 207 + 10 y ) = 8073 + 390 y \overline{2y7} \times 39 = 39(207+10y) = 8073+390y

For the tens digit to be 9 9 , we have 7 + 9 y 9 (mod 10) 7+9y \equiv 9 \text{ (mod 10)} . 9 y 2 (mod 10) \implies 9y \equiv 2 \text{ (mod 10)} and y = 8 y = \boxed 8 .

tens digit to be * 9 9 .

Vilakshan Gupta - 1 year, 2 months ago

Log in to reply

Thanks. Why don't you learn to use LaTex. I have been editing your problems. Members will read your problems and solutions if they are in LaTex.

Chew-Seong Cheong - 1 year, 2 months ago

Log in to reply

I use LaTex already. You just modify my problems slightly in a different format...and that's all ! You know sometimes I feel that I also could modify other's problems when they are badly written...lol.

Vilakshan Gupta - 1 year, 2 months ago
Chris Lewis
Mar 22, 2020

( 207 + 10 y ) × 39 = 8073 + 390 y (207+10y) \times 39 = 8073+390y

The tens digit of this is the units digit of 7 + 9 y 7+9y . Since we want this to be 9 9 , we want the units digit of 9 y 9y to be 2 2 ; this happens when y = 8 y=\boxed8 .

Srinivasa Gopal
Mar 22, 2020

(200 + 10y + 7)* 39 = 7800 + 390y + 273 = 8073 + 390y as 0<=y<=9 the different possible values of (8073 + 390y) for y =0,1,...9 are 8463,8853,9243,9633,10023,10413, 10803,11193 and 11583. This implies that y = 8

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...