Find $x$ #2

Algebra Level 1

$\large \sqrt{3x-4}+6=10$

Where $x = \dfrac ab$ and $a$ and $b$ are positive co-prime integers. Find $a+b$

2 solutions

Nazmus Sakib
Jan 10, 2018

$\sqrt{3x-4} + 6 = 10$

or, $\sqrt{3x-4} = 4$

or, $(\sqrt{3x-4})^2 = (4)^2$

or, $3x-4 = 16$

or, $3x = 20$

or, $x = \dfrac{20}{3}$

$a + b = 20 + 3 = \boxed{23}$

Khang Tran
Jan 10, 2018

3x - 4 = (10-6)(10-6) 3x - 4 = 16 3x = 20 x= 20/3 =>a/b=20/3 a+b= 23