Find x

Algebra Level 4

Find the number of real values of x satisfying

[ 3 x 1 4 ] + [ 3 x 1 2 ] + [ 3 x + 1 4 ] = 6 x + 3 4 \bigg [ \frac{3x - 1}{4} \bigg ] + \bigg [ \frac{3x - 1}{2} \bigg ] + \bigg [ \frac{3x + 1}{4} \bigg ] = \frac{ 6x + 3}{4}

[.] denotes greatest integer function


The answer is 1.

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1 solution

Christian Daang
Dec 25, 2014

If we take a look on the equation, the denominators are real and the numerators have a linear equation... So probably, you can get only a 1 real solution..

So, the answer is 1:

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