a × b a = x y a\times b^{a}=xy

a × b a = x y a\times b^{a}=xy

Where xy is a two digit number and x + y = a × b x+y=a\times b

a is not equal to b

Find xy


The answer is 24.

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1 solution

Joshua Lowrance
Feb 21, 2019

We can look at the prime factorization of numbers under 100 (because x y xy is a two digit number) in the form of a × b a a \times b^a , and see if one works.

It is fairly easy to see that a a or b b cannot equal 1 1 , because otherwise a × b a < 10 a \times b^a < 10 , and x y xy is a two digit number.

a × b a = x y a \times b^a = xy x + y = ? a × b x+y \stackrel{?}{=} a \times b
2 × 3 2 = 18 2 \times 3^2 = 18 1 + 8 2 × 3 1+8 \neq 2\times 3
2 × 4 2 = 32 2 \times 4^2 = 32 3 + 2 2 × 4 3+2 \neq 2 \times 4
2 × 5 2 = 50 2 \times 5^2 = 50 5 + 0 2 × 5 5+0 \neq 2 \times 5
2 × 6 2 = 72 2 \times 6^2 = 72 7 + 2 2 × 6 7+2 \neq 2 \times 6
2 × 7 2 = 96 2 \times 7^2 = 96 9 + 6 2 × 7 9+6 \neq 2 \times 7
3 × 2 3 = 24 3 \times 2^3 = 24 2 + 4 = 3 × 2 2+4 = 3 \times 2
3 × 3 3 = 81 3 \times 3^3 = 81 8 + 1 = 3 × 3 8+1 = 3 \times 3
4 × 2 4 = 64 4 \times 2^4 = 64 6 + 4 4 × 2 6+4 \neq 4 \times 2

These are the only two digit numbers under 100 in the form of a × b a a \times b^a . The only ones that work are x = 2 , y = 4 , a = 3 , b = 2 x=2,y=4,a=3,b=2 and x = 8 , y = 1 , a = 3 , b = 3 x=8,y=1,a=3,b=3 . However, a b a \neq b , so therefore x y = 24 xy =24 is the only solution.

How is my question?

chakravarthy b - 2 years, 3 months ago

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I like your question a lot! I found it very intriguing and I loved the unique solution to it!

Joshua Lowrance - 2 years, 3 months ago

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@Joshua Lowrance thanks

chakravarthy b - 2 years, 3 months ago

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