Finding a and b? AIME Problem

In the expansion of ( a x + b ) 2000 (ax+b)^{2000} , where a a and b b are relatively prime positive integers, the coefficients of x 2 x^2 and x 3 x^3 are equal.

Find a + b a+b .


The answer is 667.

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1 solution

Hana Wehbi
Jun 23, 2017

Using the binomial theorem ( 2000 1998 ) b 1998 a 2 = ( 2000 1997 ) b 1997 a 3 b = 666 a \binom{2000}{1998} b^{1998}a^2 = \binom{2000}{1997}b^{1997}a^3 \implies b= 666a .

Since a a and b b are relatively prime a = 1 \implies a=1 and b = 666 b=666 .

a + b = 1 + 666 = 667. a+b= 1+666= 667.

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