Finding distance is easy, isn't it ?
A(x1, y1) lies on the line 3x - 4y = 26 and B(y1, x1) lies on the line 5x - 3y + 31 = 0 . Find distance between A to B.
The answer is 9.89.
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1 solution
Here,
Point A(x1, y1) lies on 3x - 4y = 26
So, 3(x1) - 4(y1) = 26 --------------------------(1)
Also, Point B(y1, x1) lies on 5x - 3y + 31 = 0
So, 5(y1) - 3(x1) = -31 ----------------------------(2)
Adding both the equations we get,
3(x1) - 4(y1) = 26
+ -3(x1) + 5(y1) = -31
y1 = -5
Substituting the value of y1 in equation 1
3(x1) - 4. -5 = 26
3(x1) + 20 = 26
3(x1) = 26 - 20
3(x1) = 6
x1 = 2
Thus,
the two points are
A(x1, y1) = A(2 , -5)
B(y1, x1) = B(-5, 2)
Finally, Using distance formula