a 1 × a 2 × a 3 × ⋯ × a n = a 2 7 6
Find the value of n satisfying the equation above.
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That is absolutely correct.
We first note that, a m × a n = a m + n
⟹ a 1 × a 2 × × . . . × a 2 3
= a n = 1 ∑ 2 3 n = a 2 2 3 × 2 4 = a 2 7 6
⟹ n = 2 3
There is no doubt that you are 100% correct.
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Relevant wiki: Sum of n, n², or n³
a 1 × a 2 × a 3 × … × a n = a 2 7 6 a 1 + 2 + 3 + … + n = a 2 7 6 1 + 2 + 3 + … + n = 2 7 6 i = 1 ∑ n i = 2 7 6 2 n ( n + 1 ) = 2 7 6 n 2 + n = 5 5 2 n 2 + n − 5 5 2 = 0 ( n + 2 4 ) ( n − 2 3 ) = 0 n = − 2 4 , 2 3
We know that n > 0 , therefore the answer is n = 2 3