The figure above consists of four quarter circles each with radius 10 and with centers at each of the vertex of the square. Find the area of the shaded region rounded to 3 decimal places.
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The area of the sector is 3 6 0 3 0 π ( 1 0 2 ) = 3 2 5 π .
The area of the triangle is 2 1 ( 1 0 2 ) ( s i n 3 0 ) = 2 5
The area of one segment is 3 2 5 π − 2 5 .
By cosine law, the area of the square is
x 2 = 1 0 2 + 1 0 2 − 2 ( 1 0 ) ( 1 0 ) ( c o s 3 0 ) = 2 6 . 7 9 4 9 1 9 2 4
The area of the shaded region is 2 6 . 7 9 4 9 1 9 2 4 + 4 ( 3 2 5 π − 2 5 ) = 3 1 . 5 1 5