Four identical circles each with radius 5 are fitted exactly inside a square as shown above. If the area of the circle that can be fitted exactly between the four circles can be expressed as
, where
and
are coprime positive integers, find
.
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( 1 0 + d ) 2 = 1 0 2 + 1 0 2 ⟹ d = 1 0 2 − 1 0 ⟹ r = 2 d = 5 2 − 5
The area of the small circle is
A = π r 2 = π ( 5 2 − 5 ) 2 = 2 5 π ( 3 − 2 2 )
Finally,
a 2 = 3 2 = 9