Finding the area

Geometry Level 2

Four identical circles each with radius 5 are fitted exactly inside a square as shown above. If the area of the circle that can be fitted exactly between the four circles can be expressed as 25 π ( a b b ) 25\pi(a-b\sqrt{b}) , where a a and b b are coprime positive integers, find a 2 a^2 .


The answer is 9.

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1 solution

Connect the centers of the circle to form a square. Let d d be the diameter of the small circle. By pythagorean theorem, we have

( 10 + d ) 2 = 1 0 2 + 1 0 2 (10+d)^2=10^2+10^2 \implies d = 10 2 10 d=10\sqrt{2}-10 \implies r = d 2 = 5 2 5 r=\frac{d}{2}=5\sqrt{2}-5

The area of the small circle is

A = π r 2 = π ( 5 2 5 ) 2 = 25 π ( 3 2 2 ) A=\pi r^2 = \pi (5\sqrt{2}-5)^2=25\pi(3-2\sqrt{2})

Finally,

a 2 = 3 2 = a^2=3^2= 9 \boxed{\color{#20A900}9}

@Marvin Kalngan I did the same way..👍 Is there any other method?

Toshit Jain - 4 years, 1 month ago

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