Finding the digits : Modular Arithmetic

Level pending

What are the last two digits of 3 1234 3^{1234} ?


The answer is 69.

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1 solution

Mathh Mathh
Apr 15, 2015

Carmichael function says

(since λ ( 2 2 5 2 ) = lcm ( λ ( 2 2 ) , λ ( 5 2 ) ) \lambda(2^2 5^2)=\text{lcm}(\lambda(2^2),\lambda(5^2)) = lcm ( 2 , 20 ) = 20 =\text{lcm}(2,20)=20 )

3 1234 3 1234 ( m o d λ ( 100 ) ) 3 14 69 ( m o d 100 ) 3^{1234}\equiv 3^{1234\pmod {\lambda (100)}}\equiv 3^{14}\equiv \boxed{69}\pmod {100} .

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