Finding the last digit

$1234 \equiv 4 \pmod{10} \\ 5678 \equiv 8 \pmod{10} \\ \Rightarrow 1234 \times 5678 \equiv 32 \equiv 2 \pmod{10}$

Hence , the last digit of the multiplication is $2$ .

Here just we need to multiply the last two digits which is 4x8=32. So the last digit becomes 2.

8*4 = 32 (Product of last digits of both numbers)

The last digit is just $\small{\text{(product of the units digits of both numbers} = 32})$ $\pmod{10}$

$\Rightarrow \boxed{2}$ .

When we are asked about only last few digits (say last n digits) of a large sum (or a large product); we can arrive at the answer by only adding (or multiplying in case of products) last n digits of each participant of the sum (or product) and ignoring all other digits, as they can not affect the last n digits in any way no matter how large the participating numbers are.

Applicable only in additions and multiplications (but not a combination of both)

So in this problem n =1 i.e. we are asked last 1 digit of the given product. We can easily tell last 1 digit by ingoring the higher places from all participating numbers leaving just 1 digit from each and then carry out the multiplication.

So 1234 * 5678 becomes 4 * 8 which is 32, last digit is 2.

ANSWER 2

we need the last digit.so 8*4=32.according to the general rule of multiplication we will take 2.

so the last digit is 2.we don't need mod here

You just need to multiply the last digits of the multiplicand and the multiplier which is 4x8=32. Then the last digit of the product would be the answer.

If we Multiply 1234x5678 the answer will be 7006652... The question is what is the last digit of 1234x5678?

                                 1234
                               x5678
                               ---------
                         7006652<----------------The last digit is number 2.

8*4=32 So last digit is 2

multiplying the last 2 digit (8x4) the last digit is 2

Multiply ones place digit 8and 4 then last digit of solution is 2

Pretty simple. Just multiply the two last digit of the numbers. 4 x 8 = 32. Therefore the last digit is 2.

Product of last 2 digit is required

The last digits will never get added to anything ,so 4×8=32

$1234×5678\equiv(1230+4)×(5670+8)\equiv4×8\equiv32\equiv30+2\equiv\color{#FFFFFF}\colorbox{#20A900}{2}$

$\text{That was in}\mod{10}$

4x8=32 and 32%10=2

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This. doesn’t even require modular arithmetic. You just have to multiply the last digit of each number. 4*8=32, so the last digit is 2.

The product of their last digit is 32 and its last digit is $\boxed{\large{2}}$

Multiply the last digits of the two numbers which is 32. The last digit is 2.

4*8=32%10=2

multiply the last two digits which is 4x8=32. So the last digit becomes 2.

Just multiply last digiys of both numbers 4 x 8 we get 32. So 2 is the answer

sice the last digit of 1234 is 4,last digit of 5678 is 8 multiplying 4 by 8 we get 32 abd therefore 2 as a last digit so the answer is 2

Multiply the last 2 digits, the ones digit of the resultant number is the answer