Finding the mass

Algebra Level pending

A pipe is in the form of a hollow cylinder as shown in the figure above. Find its mass in kilograms when its length is 1.5 1.5 m m , its outside diameter is 300 300 m m mm , its inside diameter is 200 200 m m mm and its density is 5500 5500 k g m 3 \frac{kg}{m^3} .

Round off your answer to the nearest whole number.


The answer is 324.

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1 solution

Use the formula: m = ρ v m = ρv where: m = m a s s m=mass , ρ = d e n s i t y ρ=density and v = v o l u m e v=volume

Solving for the volume

let v v =volume of the pipe, v 1 v_1 = volume of the bigger cylinder and v 2 v_2 = volume of the smaller cylinder

v = v = v 1 v 2 = π 4 ( 0. 3 2 ) ( 1.5 ) π 4 ( 0. 2 2 ) ( 1.5 ) = 0.058904862 v_1 - v_2 = \frac{π}{4}(0.3^2)(1.5) - \frac{π}{4}(0.2^2)(1.5) = 0.058904862 m 3 m^3

Solving for the mass

m = ρ v = ( 5500 ) ( 0.058904862 ) = 324 m = ρv = (5500)(0.058904862) = 324 k g kg

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