, its outside diameter is , its inside diameter is and its density is .
A pipe is in the form of a hollow cylinder as shown in the figure above. Find its mass in kilograms when its length isRound off your answer to the nearest whole number.
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Use the formula: m = ρ v where: m = m a s s , ρ = d e n s i t y and v = v o l u m e
Solving for the volume
let v =volume of the pipe, v 1 = volume of the bigger cylinder and v 2 = volume of the smaller cylinder
v = v 1 − v 2 = 4 π ( 0 . 3 2 ) ( 1 . 5 ) − 4 π ( 0 . 2 2 ) ( 1 . 5 ) = 0 . 0 5 8 9 0 4 8 6 2 m 3
Solving for the mass
m = ρ v = ( 5 5 0 0 ) ( 0 . 0 5 8 9 0 4 8 6 2 ) = 3 2 4 k g