A boat is moving with a velocity directly away from a gun located on the bank of a river.The gun fires a shell with a speed at an angle with the horizontal.If the shell hits the boat ,then the distance of the boat from the gun at instant the shell is fired is given by What is the value of ?
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Distance to be travelled by bullet = Horizontal range distance travelled by boat = time of flight of bullet * speed of boat distance of boat from bullet when it is fired = horizontal range -(t of filght * speed of boat) = \frac{2u^2\sin\theta\cos\theta}{g} -\frac{2uv\sin\theta}{g} =1/g *2u\sin\theta(u\cos\theta-v) therefore a = 2