Firing a boat

A boat is moving with a velocity v v directly away from a gun located on the bank of a river.The gun fires a shell with a speed u u at an angle θ \theta with the horizontal.If the shell hits the boat ,then the distance of the boat from the gun at instant the shell is fired is given by s = 1 g × a u sin θ ( u cos θ v ) . s=\frac{1}{g} \times {au\sin\theta( u \cos\theta - v)} . What is the value of a a ?

none of the rest 60 2 1

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2 solutions

Shantanu Das
Apr 27, 2014

Distance to be travelled by bullet = Horizontal range distance travelled by boat = time of flight of bullet * speed of boat distance of boat from bullet when it is fired = horizontal range -(t of filght * speed of boat) = \frac{2u^2\sin\theta\cos\theta}{g} -\frac{2uv\sin\theta}{g} =1/g *2u\sin\theta(u\cos\theta-v) therefore a = 2

Abhishek Singh
Mar 22, 2014

Please reshare my problems for other to try!!!!!!!!!

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