First Law of Thermodynamics

Given 1.6 mole of gas is fixed in an enclosed cube with a volume of 38.0 c m 3 { cm }^{ 3 } . When 2465 J of heat is supplied, the pressure of the gas increases. If the molar heat capacity for the gas, C v , m { C }_{ v,m } is 30.97 J m o l 1 { mol }^{ -1 } K 1 { K }^{ -1 } , what is the change in temperature in Kelvin?

-49.75 0 49.75 1890

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1 solution

Leong Guang Ye
Nov 1, 2015

The First Law of Thermodynamics states that Δ \Delta Q= Δ \Delta U + W. Since the gas is fixed and enclosed, therefore the volume is constant. When the heat is supplied, only pressure increases, therefore there is no work done, W = 0. Hence, Δ \Delta Q = Δ \Delta U, whereby Δ \Delta U = n C v , m { C }_{ v,m } Δ \Delta T. Through substitution and calculation, the change in temperature is 49.75 K.

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