First problem from my set!

Fill the blank ? \boxed{?} .

2! \text{2!} ? \boxed{?} 2+1 \text{2+1}

This problem a part of this set math for everyone

< \large{<} > \large{>} = \large{=}

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1 solution

Matin Naseri
Jan 28, 2018

2!=2×1=2 \text{2!=2×1=2}

2+1=3 \text{2+1=3}

Thus 2!=2×1=2 \text{2!=2×1=2} < \boxed{<} 2+1=3 \text{2+1=3} .

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