First step to fermat's little theorem
Number Theory
Level
1
What is remainder if 31^102 is divided by 103
The answer is 1.
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1 solution
31^(103-1)-1 is divisible by 103(fermat's theorem) now we can write 31^102=31^(103-1)-1+1,rem(31^102/103)=rem((31^(103-1)-1+1)/103)=1