The sum of three integers which form a Geometric Progression is 6 5 . If the first term is minus by 1 and the third term is minus by 1 9 , the three integers form an Arithmetic Progression. What is the sum of these 3 integers?
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Wrong answer answer should be 45
wrong question answer must be 45 or improve your asking skills
WRONG QUESTION, NOT AT ALL CLEAR. ARE YOU ASKING ABOUT SUM OF INTEGERS IN GP OR SUM OF INTEGERS IN AP. ANSWER SHOULD BE 45 AS THE NEW INTEGERS WOULD BE 4, 15, 26.
Oops, made a mistake haha
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u could've asked the sum of the AP.
it decreased my ratings and i came down a level please check the question next time
you need to see the number in first sentence
Oops the answer appeared in the problem already! See Damiann's solution!
Actually, this problem is supposed to determine the three integers but I don't know how to ask for an integer answer so it ends up being a troll. I am very sorry and the supposed solution is as below:
Tools needed to solve the problem:
For three terms a , b , c ,
If they form A.P, then 2 b = a + c
If they form G.P, then b 2 = a c
Let the three integers be a , b , c . From the given details, we have:
b 2 = a c
a + b + c = 6 5
2 b = ( a − 1 ) + ( c − 1 9 )
From the second and third equation, we will have
b = 1 5
Substitute to the first and second equation, we will have
a + c = 5 0
a c = 2 2 5
From here we can construct an equation with the roots a , c ,
x 2 − ( a + c ) x + a c = 0
x = 5 or x = 4 5
Hence,
a + b + c = 6 5
Nice question...pity that the answer was in the question itself!!!
Actually, you could ask what is the n -th term of this GP.
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One could derive the answer from the first sentence.