Firstly an AP, then it becomes a GP!

Algebra Level 1

There are 4 integers a , b , c , d a,b,c,d where the first three terms ( a , b , c ) (a,b,c) form an Arithmetic Progression while the last three terms ( b , c , d ) (b,c,d) form a Geometric Progression. Given that the sum of the first and the last term ( a + d ) (a+d) is 37 37 and the sum of the second and third term ( b + c ) (b+c) is 36 36 . Find the sum of these 4 integers a , b , c , d a,b,c,d .


The answer is 73.

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3 solutions

Takeda Shigenori
Mar 16, 2014

37+36=73...

that's what i think :D

Dixie Hyun - 7 years, 2 months ago
Tristan Shin
Mar 18, 2014

The sequence is 12, 16, 20, 25. Summing, we get 73.

Alternatively, just add the two sums given in the final sentence to get 73.

Damiann Mangan
Mar 11, 2014

One could derive the answer from the last two sentence on the problem.

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