What is the area of the largest right triangle which can be inscribed in a circle of radius 5 units?
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By imagining the biggest possible right triangle that can be drawn inside a circle, the hypotenuse of the right triangle must be the diameter of the circle. Thus, forming an isosceles right triangle. The diameter is 5 x 2 = 10 units. By 45-45-90 Triangle theorem (the hypotenuse of 45-45-90 triangle is equal to the length of a leg times the square root of two.) Two legs = 5√2 units. Area of Triangle = (bh)/2 = [(5√2)(5√2)]/2 = (25 x 2)/2 = 25 square units.