Fizzy Clockwork

If you pay close attention, you'll find that the bubbles in a glass of champagne form a steady stream and leave the surface of the glass i​n regular time intervals, Δ t \Delta t . Why is this?

The bubbles occur due to vibrations in the room that have a constant frequency It takes a constant amount of time for gas from the air to make it to the growing bubble The bubbles rise when the buoyant force exceeds the adhesive force The bubbles form due to pressure waves in the champagne that have a constant wavelength

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1 solution

Josh Silverman Staff
Nov 22, 2015

Bubbles grow at the surface of a champagne glass when gas dissolved in the champagne is absorbed into a growing bubble at an imperfection in the glass.

When the bubble is small, the buoyant force pulling it upward is small compared to the adhesive force keeping it stuck to the surface. As the bubble grows, the buoyant force increases linearly in the volume ( V \sim V ), while the adhesive force is proportional to the surface area of the bubbles, or V 2 / 3 \sim V^{2/3} . Clearly, at some point, the buoyant force must overtake the adhesive force, at which point the bubble breaks free from the imperfection in the surface, and rises to the surface.

Assuming deterministic physics, the timing of the initiation of bubble formation, as well as the dynamics of the growth of the bubble should be identical for each bubble, and thus take an identical amount of time from start to finish, thus explaining the constant time intervals between bubble release.

Does the formation of bubbles ever stop?

Agnishom Chattopadhyay - 4 years, 11 months ago

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At some point, enough gas will have escaped the champagne so that the amount of gas that remains corresponds to the solubility of the gas in champagne at the ambient pressure, then the bubbles should stop forming.

Josh Silverman Staff - 4 years, 11 months ago

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