Flipping a coin pt.4 (Mediocre....)

I have two coins and two 10 sided dice. All are fair. I flip each coin once and roll each dice twice. What is the probability that I get two heads and four 10s (assuming it follows the laws of probability)? Give your answer in decimal form.


The answer is 0.000025.

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2 solutions

Magnus Käärik
Mar 10, 2019

Just find the product of all the probabilties that result in a win. Getting a head is 1/2 so doing it twice is 1/2*1/2=1/4. rolling a ten is 1\10 so doing it 4 times is (1/10)^4=1/10000. so the probabilty of both happening is 1/10000×1/4=1/40000=0.000025.

1/2 x 1/2 x (1/10)^4 = 2.5x10^-5 =0.000025

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