Floating box

A box with density ρ = 800 kg/m 3 \rho = 800 \text{ kg/m}^3 is floating face down on a fluid with density ρ f = 1200 kg/m 3 . \rho _{f} = 1200 \text{ kg/m}^{3}. If the box has a height of H = 6.0 cm , H= 6.0 \text{ cm}, by what depth h h is the box submerged?

The floating box is a rectangular parallelepiped.

4 cm 4 \text{ cm} 2 cm 2 \text{ cm} 3 cm 3 \text{ cm} 5 cm 5 \text{ cm}

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1 solution

Sowmitra Das
Jul 20, 2014

Let, Cross-Sectional Area of the Box be A A .
\therefore Volume of liquid displaced by box = A h =A\cdot h
So, Weight of Displaced liquid = ρ f A h g =\rho_f \cdot Ah\cdot g .
Again, Weight of the box = ρ A H g =\rho\cdot AH\cdot g .
\therefore From Archimedes' Principle, we have,
ρ f A h g = ρ A H g h = ρ H ρ f = 4 \displaystyle \rho_f \cdot Ah\cdot g=\rho\cdot AH\cdot g\Rightarrow h=\frac{\rho\cdot H}{\rho_f}=\boxed{4} cm.

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