A solid uniform cylinder of length 150 mm and diameter 75 mm is to float upright in water. Determine the limits within which its mass should lie.......
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brilliant sir!
Great reasoning sir..
I agree to the explanations given by Mr Seth Zenz.The cylinder will not float upright,thoughvolume calculations and density factor taken in to consideration. Theoritically it is O.K.
K.K.GARG.India
great sir!
supeb brilliant sir
Brilliant sir!!........
Nice
Actually perfect answer sir!
very good sir
thank you sir !!!!
Thanks for explanation sir....
Thanks you Mr.Seth Zenz
ok sir
i liked it sir. it was mind twisting.....:)
a great question. thank you sir! keep posting such questions please.
marvellous sir seth
THE CYLINDER WILL FLOAT IF IT'S DENSITY IS LESS THAN OR EQUAL TO THE DENSITY OF WATER i.e. 1000KG PER CUBIC METERS. FIRST CALCULATE THE VOLUME OF CYLINDER THAT COMES OUT TO BE .00066234 CUBIC METERS. NOW USE THE FORMULA FOR DENSITY WHICH IS MASS DIVIDED BY VOLUME AND PUT IT EQUAL TO 1000.
Calculate the volume of the given cylinder. Then apply Density=Mass/Volume. (D(water)=1000 kg/m3) Mass comes to be the above mentioned value.
Volume =0.6629 m cube , m/v = density , water has 1 as desity , which means the mass has to be less than o.6629 to float , else will sink , hope it is correct
using the first law of flotation mass of the floating body = mass of liquid displaced during fully immersed flotation densities of the body and liquid are equal
With due respect to the solution I would like to ask how we can be so sure that the body gets fully immersed.
it says floting but how much is it immersed is not specified!!
Apply Archimedie's Principle : Body will float on the water if mass of replace water is greater or equal to mass of body. Volume of cylinder = PiXr^2Xh =662343X10^-9 cube mtr Density of water = 1000 Kg/cube mtr Max mass of cylinder = VolumeXdensity of water = .663 Kg
ya if this was asked for a theoretical answer then the ans would be diff. but for objective the ans c is best because others are easily eliminated ..........
just calc the vol of cyl. and multy it wid 1 {dinsty of watr } and you know the ans
For a body to float over the surface of water; Its density should be less than 1000kg/m3....So find out the volume of cylinder(v), therefore Mass to float over water=1000*v
First of all we must find the volume of that cylinder 15 3.5 3.5*3.14 (height=15 Cm,radius=3.5 Cm) then we will get the volume 662.32 (around) after converting it into water weight we will get the answer above following.........
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Because this was a multiple-choice problem, I think I was able to compute the upper limit and get the answer without having a full understanding of the lower limit. V = π r 2 h = 0 . 6 6 2 7 L . If the object weighs more than 0.6627 kg it is denser than water and will sink. This already eliminates all the answers but one.
The lower bound can be calculated, I suppose, from knowing that the cylinder cannot float upright if it is less than half immersed in water - it would fall on its side. So you'd start by calculating the buoyant force if it's only half immersed and balancing it against gravity. But I haven't gone through and done this.