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1 solution
It is an isosceles triangle with vertex angle 60 degrees.
So it is an equilateral triangle.
So its area is 4 3 ∗ ( 4 7 5 ) 2 = 4 1 5 . S i n c e t h e t o p v e r t e x a n g l e i s h a l f t h a t o f t h e o n e a t t h e m i d d l e b y t h e s a m e h o r i z o n t a l s i d e , t h e m i d d l e p o i n t i s t h e c i r c u m c e n t e r . ∴ t h e b l u e a r e a = 3 1 t r i a n g l e a r e a . ∴ b l u e a r e a = 3 1 ∗ 4 1 5 = 1 . 2 5 .