Floor , Absolute, Inverse, Sawtooth And Periodic Also

Geometry Level 5

Let f ( x ) = sin 1 ( m 2 3 m + 1 ) sec ( x 3 ) e m 4 ( sin { x } ) f(x) = \sin^{-1} (m^2-3m+1) \sec \left( \dfrac{|x|}3 \right) - \lfloor e^{m-4} \rfloor (\sin \{ x \} ) .

If f ( x ) f(x) is periodic, find the number of possible non-negative integral value(s) of m m .

Notations :


The answer is 4.

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1 solution

Yashas Ravi
Jul 8, 2019

First of all, m 2 3 m + 1 1 m^2-3m+1≤1 and m 2 3 m + 1 1 m^2-3m+1≥-1 . The union of these inequalities shows 0 m 1 0≤m≤1 and 2 m 3 2≤m≤3 . Since the question asks for non-negative integral values, m m can be 0 0 , 1 1 , 2 2 , or 3 3 . Also, e m 4 = 0 ⌊e^{m-4}⌋=0 since m = 0 m=0 , 1 1 , 2 2 , or 3 3 are all less than 4 4 . As a result, the latter part of the function becomes 0 0 . Since for the 4 4 possible values for m m , a r c s i n ( m 2 3 m + 1 ) arcsin(m^2-3m+1) is not 0 0 and k* s e c ( x 0.3333 ) sec(|x|*0.3333) is periodic for some real number k k , there are 4 4 possible values for m m that make f ( x ) f(x) periodic.

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