Find the last 7 digits (from left to right) of ⌊ 1 0 3 3 3 3 + 2 0 1 6 1 0 9 9 9 9 ⌋ .
Notation : ⌊ ⋅ ⌋ denotes the floor function .
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Hi Sir, it would be good if you could put 2 0 1 6 2 = ( 2 0 0 0 + 1 6 ) 2 = ( 4 0 0 0 0 0 0 + 6 4 0 0 0 + 2 5 6 ) = 4 0 6 4 2 5 6 .
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Oh, I just used a calculator for that. I think it is not the main purpose of the solution.
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⌊ 1 0 3 3 3 3 + 2 0 1 6 1 0 9 9 9 9 ⌋ = ⌊ 1 0 3 3 3 3 + 2 0 1 6 1 0 9 9 9 9 + 2 0 1 6 3 − 2 0 1 6 3 ⌋ = ⌊ 1 0 3 3 3 3 + 2 0 1 6 ( 1 0 3 3 3 3 + 2 0 1 6 ) ( 1 0 6 6 6 6 − 2 0 1 6 ⋅ 1 0 3 3 3 3 + 2 0 1 6 2 ) − 2 0 1 6 3 ⌋ = ⌊ 1 0 6 6 6 6 − 2 0 1 6 ⋅ 1 0 3 3 3 3 + 2 0 1 6 2 − 1 0 3 3 3 3 + 2 0 1 6 2 0 1 6 3 ⌋ = 1 0 6 6 6 6 − 2 0 1 6 ⋅ 1 0 3 3 3 3 + 2 0 1 6 2 − 1 = 3 3 2 9 digits 9 9 9 . . . 9 9 9 7 9 8 4 3 3 3 3 digits 0 0 0 . . . 0 0 0 + 4 0 6 4 2 5 6 − 1 = 3 3 2 9 digits 9 9 9 . . . 9 9 9 7 9 8 4 3 3 2 6 digits 0 0 0 . . . 0 0 0 7 digits 4 0 6 4 2 5 5