Floor function, integral, and others

Calculus Level 3

The value of 1 ( 1 x 1 x ) d x \displaystyle \int_1^\infty \left (\dfrac {1}{\lfloor x\rfloor }-\dfrac{1}{x}\right) dx is

1.282 0.577 The integral diverges 0.693

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Naren Bhandari
Jul 7, 2020

The expression is equal to lim n ( k = 1 , Δ k = 1 n Δ k k 1 n d x x ) = lim n ( H n ln n ) = lim n ( γ + ln n + 1 2 n O ( n 2 ) ln n ) = γ \begin{aligned} \lim_{n\to\infty}\left(\sum_{k=1 , \Delta k=1}^n\frac{\Delta k}{k} -\int_1^n\frac{dx}{x}\right)&= \lim_{n\to \infty}(H_n - \ln n)\\&= \lim_{n\to\infty} \left(\gamma +\ln n+\frac{1}{2n}-O(n^{-2})-\ln n\right)=\gamma\end{aligned}

integration is from 1 to n .

Paramananda Das - 11 months, 1 week ago

Log in to reply

Fixed it. Thank you.

Naren Bhandari - 11 months, 1 week ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...