Floor Functions?
Algebra
Level
3
Where, represents Greatest Integer Function.
Then, "x" belongs to
[3,4]
[2,4)
(2,3)
None Of These
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1 solution
We may solve this equation as if it was any other second degree polynomial equation (because the solution set of the original equation must be a subset of it). Then x 2 − 5 x + 6 = ( x − 2 ) ( x − 3 ) = 0 . Therefore the two solutions to this equation already are integers which makes the only possible interval that which contains the points x = 2 and x = 3 .