Floor system of equations

Algebra Level 3

{ x + y + { z } = 1.1 x + { y } + z = 2.2 { x } + y + z = 3.3 \begin{cases} x+ \lfloor y \rfloor+ \left \{ z \right \}=1.1\\ \lfloor x \rfloor+ \left \{ y \right \}+z=2.2 \\ \left \{ x \right \}+y+\lfloor z \rfloor=3.3 \end{cases}

Find the solution to the system of equations and submit your answer as x + y + z x+y+z .

Notations :


The answer is 3.3.

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1 solution

Abhay Tiwari
May 9, 2016

Adding all the three equation gives us the result 2 x + 2 y + 2 z = 6.6 2x+2y+2z=6.6

From there it can be said that x + y + z = 3.3 x+y+z=\boxed{3.3}

Yes, Was quite easy

Md Zuhair - 3 years, 7 months ago

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