Two identical barrels are filled with the same volume of water. The barrels have identical holes in their bottoms (which begin plugged) but barrel A also has one in its top (which is always open).
At time zero, the plugs are removed and the water starts to flow out of the bottom, as shown in the figure.
Which barrel will empty first?
Assume that the holes are the same size and shape.
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what???? this is partially right and not the correct explanation
Plus, if it has a hole on the top, that allows pressure from kilometres of air above, to seep through.
What are the main forces to be considered? I would like to know if the mass of the water influences the rate at which the water flows out? And what about the size of the hole on top in relation to the size of the hole on the bottom? And what causes the suction effect, and what forces are playing out when there is a vacuum?
i think the answer is that I'm the most savage and I'm the most dope
But tell one thing if the top hole was always there so it was there even before the experiment so the final pressure in both is same so same effect shud be there
since the additional hole on A reduces the pressure differential between inside of the can and outside , flow of liquid due to pressure differential will be less in A than in B. so the can A must take more time to get empty than B . Isn't it ?
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Nope,,It increases the flow in Barrel in A than in B
Think about what's happening above the liquid remaining in B as the water flows out. A vacuum is forming which has much lower pressure than the atmosphere outside.
Hasn't anybody here ever punched a hole in the bottom of a beer can before chugging it ?
haha!!nice solution!
I prefer to do it on my bottles of rum personally!
You've reminded me of my student days (which I miss).
Only cans with concentrated sugar milk.
Gravity Bongs same concept lol 420 science
I think barrel a is going to empty out first because it has a hole on the top too. I think logical reasoning works best. To figure this problem out I tested the same thing but using an egg. The egg with only one hole in it didn't empty out as quickly as the other egg. I would rate this problem a 1 because I got to do it in real life which gave me a clear answer.
think-
for barrel A-air will pass through the upper hole which will create an extra pressure to the water inside the barrel.if the air pressure is very high it will create a lot pressure on barrel A and the water flow through the lower hole will be faster.
example. when we open a bottle and drop the water it goes at normal speed.but when we pressurize the bottle from outside the speed of the water flow increases.
for barrel B-as no external force is working water will come out at normal speed.
For A - discharge will be influenced by the atmospheric pressure of air coloum and the water coloum above the bottom hole For B - Discharge will be influenced only by the pressure of the water coloum above the bottom hole
To explain this problem all you need to know is the fact that Barrel A has two holes on in the top and bottom Barrel B does not. Barrel A will empty faster because of the hole in the top allows airflow which would prevent air having to go in the bottom of barrel b to get oxygen to push more water out. Imagine if you were to take a glass bottle pour the water out it won't go but so fast because there is no airflow pushing the water out. But take that same bottle and drill a medium sized hole at the bottom that would let the airflow through the bottle letting it pour out faster.
What does oxygen have to do with it?
Key solution is pressure. In A: atmospheric pressure+ pressure of air on top of liquid
Barrel A's hole at the top lets air in that would push the water down "barely" faster.
As barrel A has hole at the top it allows the air to fill the upper space of barrel or fill the space of draining water and it leads air presure to act on the water and it will add addition force on water which will lead to fast drainage of water....
Anytime when you try to empty a container with liquid in it, there needs to be some kind of matter to take place of the empty matter. In this case, the water will be able to freely flow out of the container with the air hole ventilation because as water is getting emptied, the matter exchange is constantly being filled with air. In the case of no hole or ventilation, there still need to be some sort of matter to replace the matter leaving, so air goes through the hole where the water is also getting emptied, and that's where you get that sound of gluging.
Since there is a hole on the top of barrel A, atmospheric pressure acts on the liquid which makes it flow out in greater pressure compared to barrel B in which there is no hole at the top thus less pressure is exerted on the liquid in barrel B which may even result in little or no liquid flow from it.
In barrel b both discharge of water and thereby intake of air is done by same hole thereby extending the length of time, assuming the volume of barrel and water is not negligible. :p
Becoz of atmospheric pressure in A... It gets empty first...
Pressure at the bottom of tank A is P=height of the liquidxdensity of the liquidxg + atmospheric pressure> pressure at the bottom of tank B only heightxdensityxg .Therefore discharge velocity of liquid at tank A is more than the tank at B(Bernouilli theorem; pressure converts to velocity )
Another way to think about this, volume "wants" to remain constant so the only way for this to happen is for the hole in bottom B to alternate between allowing air in/water out.. glug.. glug.. glug.. effectively cutting the fliw rate ~1/2.
Or if large enough to allow both to flow, reducing the effective area of the hole to allow some air in.
Hole in barrel A maintains atmospheric pressure on top of fluid surface in barrel A. Absence of hole and inturn absence of exposure to atmospheric pressure creates a vacuum inside barrel B when fluid flows out.
Air pressure will be added to the pressure off the liquid inside the barrel
It is due to the extra air pressure in A
The first barrel is using intake and outtake system that air flows through it therefore increases the speed of water dropping while the second barrel only has outtake so it is slower.
If we apply Bernoulli equation at opening of the hole and the surface of water. In case of A , the pressure of surface of water is equal to atmospheric pressure , but in second case its zero ( vaccum) . so on applying the Bernoulli equation we get the answer
In the case of Barrel B, P1V1=P2V2 so P2=P1(V1/V2). As the barrel empties and the volume of gas increases (V2>V1) the pressure driving the flow will drop proportionally. Since the hole in Barrel A is open to the atmosphere there is a constant pressure driving the flow that does not diminish over time.
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The second hole allows air to fill the space emptied by the fluid. In B one hole is being used for both intake of air and out flow of the fluid.