Flowers And Sparrows

Algebra Level 2

In a village, there was a lotus pond where a few lotus flowers were blooming. Some sparrows came and each sat on a different lotus flower, leaving one sparrow no lotus flower on which to sit. Then the sparrows rearranged themselves and sat in pairs, one pair per lotus flower; this left one lotus flower without any sparrows. Find the number of lotus flowers in the pond.


The answer is 3.

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3 solutions

Chew-Seong Cheong
Jun 15, 2016

Relevant wiki: Setting Up Equations

Let the number of flowers be n n . Then the number of birds is n + 1 n+1 . When the birds were sitting in pairs, there was a flower left empty. Therefore,

n + 1 2 = n 1 n + 1 = 2 n 2 n = 3 \begin{aligned} \frac {n+1}2 & =n-1 \\ n+ 1 &= 2n-2 \\ \implies n&= \boxed {3}\end{aligned}

Venkatachalam J
Jun 14, 2016

Total Number of Flowers=3

Umer Khalid
Jun 19, 2016

Let, sparrows are denoted by s and flowers are denoted by f then " Some sparrows came and each sat on a different flower, leaving one sparrow no flower to sit on" implies

s-1 = f

and sparrows sat in pairs on different flowers, this time leaving one flower without any sparrows implies

s/2 = f-1

and from later equation

s = 2f-2

placing in 1st equation

(2f-2)-1=f

2f-f-2-1=0

f-3=0 => f=3

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