Fluids
Classical Mechanics
Level
3
Two bodies are in equilibrium when suspended in a liquid from the arms of a balance . the mass of one body is 96 g and its density is 24 g cm-3. the mass of the other body is 124 g and its density is 15.5 g cm-3. then the density of the liquid is:
1 g cm-3
39.5 g cm-3
8.5 g cm-3
7 g cm-3
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1 solution
M 1 = 9 6 g , ρ 1 = 2 4 g / c m 3 , V 1 = 4 c m 3
M 2 = 1 2 4 g , ρ 2 = 1 5 . 5 g / c m 3 , V 2 = 8 c m 3
Now, let density of liquid be ρ
As weights are balanced
M 1 g − V 1 ρ g = M 2 g − V 2 ρ g M 2 − M 1 = ( V 2 − V 1 ) ρ 2 8 = 4 ρ ρ = 7 g / c m 3
@VinayakSrivasta