Fluids#4

The work done in blowing a soap bubble of radius 10 cm is x × 1 0 4 J x \times 10^{-4} \text{ J} . (Surface Tension-0.03 N/m). Find x x and submit the answer to one decimal digit.


The answer is 75.4.

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1 solution

E Koh
Jan 3, 2019

Work done = Energy stored in the bubble = 2 x S x A = 2 x 0.03 x 4(pi)r^2 = 2 x 0.03 x 4(pi)(0.1)^2 = 7 539.822 369 x 10^(-6) J = 75.4 x 10^(-4) J.

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