Flux Rule- Check that out!

In the given figure, the magnetic field B=1 T points into the page. The dimensions of the loop are as shown in the figure. What is the instantaneous reading of the ammeter (in A) when the switch is thrown from the position, a to b in time t=0.1 s?

Assume that half of the loop is outside the magnetic field.


The answer is 0.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Somsubhra Ghosh
Dec 15, 2015

Although there is a flux change through the concerned loop, but there is no force to drive current in the loop. This is actually a flux rule paradox. We often tend to say that whenever there is a change of magnetic flux through a loop, an emf is induced in the loop. However, that flux change should either be due to the motion of the conductor (the driving force here being the Lorentz force) or due to a changing magnetic field (the driving force here being an induced electric field), but it should not be due to switches and the like, as is the case here.

So here no emf is induced and the current flowing is zero.

But the area changed

Sathyam Tripathi - 5 years, 4 months ago

Log in to reply

Yes its true that the area changed, but only a change in the area will not set up an emf or drive current in the loop. To set the charges moving you need to have some kind of a force as Lorentz or an electric field. Here now such force is present. So, as I have mentioned in my solution, a flux change caused due to just anything won't drive a current, the cause should be such that the flux change is accompanied by a driving force.

Somsubhra Ghosh - 4 years, 7 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...