Fly puzzle

Algebra Level 2

Two cyclists start twenty miles apart and head toward each other each going at a steady rate of 10 m.p.h. At the same time, a fly that travels at a steady 15 m.p.h. starts from the front wheel of the southbound bicycle and flies to the front wheel of the northbound one, then turns around and flies to the front wheel of the southbound bicycle again, and continues in this manner till he is crushed between the two front wheels. What total distance will the fly cover before being squashed between the bike tires.


The answer is 15.

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3 solutions

Marvin Kalngan
May 21, 2020

The two cyclists are headed to each other until collision. The time frame until collision is also the time frame the bird travels. The time frame until collision is

d = Vt \text{d = Vt}

10 miles = (10 mph)(t) \text{10 miles = (10 mph)(t)}

t = 1 hour \text{t = 1 hour}

The total travel distance of the fly is

d f l y = V f l y t = ( 15 m p h ) ( 1 h o u r ) = 15 miles d_{fly} = V_{fly}t = (15 mph)(1 hour) = \boxed{\text{15 miles}}

I vaguely remember my undergrad director of studies in applied maths mentioning this problem. It was all fine until he asked, "and just before the cyclists meet, which way will the fly be facing?"

Chris Lewis - 1 year ago

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And what was your answer? :)

Joshua Olayanju
May 20, 2020

Both travel at 10 mph so in one hour the both will reach the center and collide. This means the fly has one hour for its travels. In that time it travels 15 miles.

Total distance = 20 =20 miles

Speed of Cycle 1 = 10 _1 = 10 mph

Speed of Cycle 2 = 10 _2 = 10 mph

Since the cycles are moving in opposite directions,

Relative speed = 10 = 10 mph + 10 + 10 mph = 20 =20 mph

Relative speed = 20 =20 mph

Total distance = 20 =20 miles

Time taken = = Total distance ÷ \div Relative speed = 1 = 1 hour

The fly runs around for 1 1 hour.

Speed of fly = 15 =15 mph

Hence, it travels 15 \boxed{15} miles.

Nice Vinayak try this other problem I made https://brilliant.org/problems/real-algebra/

Joshua Olayanju - 1 year ago

Can you solve it?

Joshua Olayanju - 1 year ago

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I have done it. I am writing the solution.

Vinayak Srivastava - 1 year ago

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