Folding Rectangle!

Geometry Level pending

A rectangle with dimensions 5 -in by 10 -in 5 \text{-in by } 10\text{-in} is folded in a way such that two of its corners collide as shown in the figure. Find the area of the shaded region.

20.513 21.345 16.786 15.625

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1 solution

Hana Wehbi
Jun 12, 2016

By looking at the graph, we see that x + y = 10 y = 10 x x+y=10 \implies y=10-x and we know by Pythagoras we have:

x 2 + 5 2 = y 2 = ( 10 x ) 2 x^{2}+5^{2}= y^{2}= (10-x)^{2} ;

x 2 + 25 = 100 20 x + x 2 x^{2}+25=100-20x+x^{2} ;

20 x = 75 x = 75 20 = 3.75 y = 6.25 \implies 20x=75 \implies x=\frac{75}{20}= 3.75 \implies y=6.25 ;

The area of the two white triangles= 2 × 1 2 × ( 3.75 ) × ( 5 ) = 18.75 2 \times \frac{1}{2} \times (3.75)\times (5)= 18.75 ;

The area of the unfolded rectangle= 5 × 10 = 50 5\times 10= 50 ;

The area of shaded region: 50 18.75 2 = 15.625 \frac{50-18.75}{2}=15.625 .

Remark: the two white triangles have sides 5 , x , 5,x, and hypotenuse y y .

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