cos
2
(
a
)
1
+
1
+
sin
2
(
a
)
1
+
1
+
sin
4
(
a
)
2
+
1
+
sin
8
(
a
)
4
If sin 1 6 ( a ) = 5 1 , evaluate the expression above.
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Yes. This is just the repeated use of difference of squares: x 2 − y 2 = ( x + y ) ( x − y ) .
I'm curious whether there's any alternative solution.
The expression turns to 1 − s i n 1 6 ( a ) 8 Substitute the value provided to obtain the answer 10.
It would be better to explain how the expression finally becomes 1 − sin 1 6 ( a ) 8 .
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