For JEE practice

Calculus Level 5

Note: We likely should make the assumption that n n is restricted to being an integer.


- If the number of points of discontinuity is k k for

lim n ln ( 1 + x ) x 2 n sin x 1 + x 2 n \large{\displaystyle \lim_{n\to \infty} \dfrac{\ln(1+x)-x^{2n}\sin x}{1+x^{2n}}}

- If the area bounded by x y = 2 ( 2 x ) xy=2(\sqrt{2}-x) is l s q u n i t s l~sq~units

- If 0 π sin ( 2013 x ) + sin ( 2014 x ) + sin ( 2015 x ) . d x = m \displaystyle \int_{0}^{\pi} |\sin(2013x)|+|\sin(2014x)|+|\sin(2015x)|.dx=m

- if lim n n sin ( 2 π 1 + n 2 ) = t \displaystyle \lim_{n\to \infty} n \sin (2 \pi \sqrt{1+n^{2}})=t

- If number of solution of sin 4 π x = ln x \sin^{4} \pi x=\ln x is\are p p

Find k + l + m + t + p k+l+m+t+p


The answer is 18.425.

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